Base | Representation |
---|---|
bin | 10100101101101001… |
… | …01000001100101101 |
3 | 1001200222211102211101 |
4 | 22112310220030231 |
5 | 140233300010013 |
6 | 5035242523101 |
7 | 542400046666 |
oct | 122664501455 |
9 | 31628742741 |
10 | 11120313133 |
11 | 4797143936 |
12 | 21a4206491 |
13 | 1082b30c57 |
14 | 776c6c36d |
15 | 4514078dd |
hex | 296d2832d |
11120313133 has 2 divisors, whose sum is σ = 11120313134. Its totient is φ = 11120313132.
The previous prime is 11120313121. The next prime is 11120313143. The reversal of 11120313133 is 33131302111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6839620804 + 4280692329 = 82702^2 + 65427^2 .
It is a cyclic number.
It is not a de Polignac number, because 11120313133 - 217 = 11120182061 is a prime.
It is a super-2 number, since 2×111203131332 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11120313133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11120313143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560156566 + 5560156567.
It is an arithmetic number, because the mean of its divisors is an integer number (5560156567).
Almost surely, 211120313133 is an apocalyptic number.
It is an amenable number.
11120313133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120313133 is an equidigital number, since it uses as much as digits as its factorization.
11120313133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11120313133 its reverse (33131302111), we get a palindrome (44251615244).
The spelling of 11120313133 in words is "eleven billion, one hundred twenty million, three hundred thirteen thousand, one hundred thirty-three".
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