Base | Representation |
---|---|
bin | 10100101101101001… |
… | …01000001111111101 |
3 | 1001200222211110010002 |
4 | 22112310220033331 |
5 | 140233300011331 |
6 | 5035242524045 |
7 | 542400050414 |
oct | 122664501775 |
9 | 31628743102 |
10 | 11120313341 |
11 | 4797144005 |
12 | 21a4206625 |
13 | 1082b31087 |
14 | 776c6c47b |
15 | 4514079cb |
hex | 296d283fd |
11120313341 has 2 divisors, whose sum is σ = 11120313342. Its totient is φ = 11120313340.
The previous prime is 11120313329. The next prime is 11120313367. The reversal of 11120313341 is 14331302111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7258188025 + 3862125316 = 85195^2 + 62146^2 .
It is a cyclic number.
It is not a de Polignac number, because 11120313341 - 210 = 11120312317 is a prime.
It is a super-2 number, since 2×111203133412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11120313371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560156670 + 5560156671.
It is an arithmetic number, because the mean of its divisors is an integer number (5560156671).
Almost surely, 211120313341 is an apocalyptic number.
It is an amenable number.
11120313341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120313341 is an equidigital number, since it uses as much as digits as its factorization.
11120313341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11120313341 its reverse (14331302111), we get a palindrome (25451615452).
The spelling of 11120313341 in words is "eleven billion, one hundred twenty million, three hundred thirteen thousand, three hundred forty-one".
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