Base | Representation |
---|---|
bin | 110011110010010100… |
… | …0011110111010101111 |
3 | 101122001102020100101122 |
4 | 1213210220132322233 |
5 | 3310224230000142 |
6 | 123031132131155 |
7 | 11014613255246 |
oct | 1474450367257 |
9 | 348042210348 |
10 | 111210000047 |
11 | 43189167053 |
12 | 19678006abb |
13 | a6440b2c73 |
14 | 554db9795d |
15 | 2d5d45b1d2 |
hex | 19e4a1eeaf |
111210000047 has 2 divisors, whose sum is σ = 111210000048. Its totient is φ = 111210000046.
The previous prime is 111210000017. The next prime is 111210000101. The reversal of 111210000047 is 740000012111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111210000047 - 210 = 111209999023 is a prime.
It is a super-2 number, since 2×1112100000472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111210000017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605000023 + 55605000024.
It is an arithmetic number, because the mean of its divisors is an integer number (55605000024).
Almost surely, 2111210000047 is an apocalyptic number.
111210000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
111210000047 is an equidigital number, since it uses as much as digits as its factorization.
111210000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 111210000047 its reverse (740000012111), we get a palindrome (851210012158).
The spelling of 111210000047 in words is "one hundred eleven billion, two hundred ten million, forty-seven", and thus it is an aban number.
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