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111211021153 is a prime number
BaseRepresentation
bin110011110010010110…
…0011000001101100001
3101122001111011020002101
41213210230120031201
53310230010134103
6123031210050401
711014625040241
oct1474454301541
9348044136071
10111211021153
11431897a4241
1219678419a01
13a64437c97b
14554dd81b21
152d5d5ada1d
hex19e4b18361

111211021153 has 2 divisors, whose sum is σ = 111211021154. Its totient is φ = 111211021152.

The previous prime is 111211021127. The next prime is 111211021157. The reversal of 111211021153 is 351120112111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101845233424 + 9365787729 = 319132^2 + 96777^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111211021153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111211021153.

It is not a weakly prime, because it can be changed into another prime (111211021157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605510576 + 55605510577.

It is an arithmetic number, because the mean of its divisors is an integer number (55605510577).

Almost surely, 2111211021153 is an apocalyptic number.

It is an amenable number.

111211021153 is a deficient number, since it is larger than the sum of its proper divisors (1).

111211021153 is an equidigital number, since it uses as much as digits as its factorization.

111211021153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 111211021153 its reverse (351120112111), we get a palindrome (462331133264).

The spelling of 111211021153 in words is "one hundred eleven billion, two hundred eleven million, twenty-one thousand, one hundred fifty-three".