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1112111211120 = 2435713371399901
BaseRepresentation
bin10000001011101110111…
…111100110001001110000
310221022112221110001001120
4100023232333212021300
5121210100432223440
62210521414502240
7143230103215650
oct20135677461160
93838487401046
101112111211120
11399709871188
1215b64b964980
1380b43caa4a0
143bb7db94360
151ddddd8cdd0
hex102eefe6270

1112111211120 has 640 divisors, whose sum is σ = 4389605713920. Its totient is φ = 226636185600.

The previous prime is 1112111211091. The next prime is 1112111211149. The reversal of 1112111211120 is 211121112111.

It is an interprime number because it is at equal distance from previous prime (1112111211091) and next prime (1112111211149).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1112111211120.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 112318170 + ... + 112328070.

It is an arithmetic number, because the mean of its divisors is an integer number (6858758928).

Almost surely, 21112111211120 is an apocalyptic number.

1112111211120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1112111211120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2194802856960).

1112111211120 is an abundant number, since it is smaller than the sum of its proper divisors (3277494502800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1112111211120 is a wasteful number, since it uses less digits than its factorization.

1112111211120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10113 (or 10107 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 15.

Adding to 1112111211120 its reverse (211121112111), we get a palindrome (1323232323231).

Subtracting from 1112111211120 its reverse (211121112111), we obtain a palindrome (900990099009).

It can be divided in two parts, 1112111 and 211120, that added together give a palindrome (1323231).

The spelling of 1112111211120 in words is "one trillion, one hundred twelve billion, one hundred eleven million, two hundred eleven thousand, one hundred twenty".