Base | Representation |
---|---|
bin | 11001010010010101100110… |
… | …000101111000011001101111 |
3 | 112120202200210210002211200101 |
4 | 121102111212011320121233 |
5 | 104034041221024404403 |
6 | 1032305433312211531 |
7 | 32265515466324634 |
oct | 3122254605703157 |
9 | 476680723084611 |
10 | 111211301013103 |
11 | 324874a2170735 |
12 | 105815b3839ba7 |
13 | 4a09246c77765 |
14 | 1d669272d418b |
15 | ccccdb5eb71d |
hex | 65256617866f |
111211301013103 has 2 divisors, whose sum is σ = 111211301013104. Its totient is φ = 111211301013102.
The previous prime is 111211301012983. The next prime is 111211301013187. The reversal of 111211301013103 is 301310103112111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111211301013103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111211301013203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605650506551 + 55605650506552.
It is an arithmetic number, because the mean of its divisors is an integer number (55605650506552).
Almost surely, 2111211301013103 is an apocalyptic number.
111211301013103 is a deficient number, since it is larger than the sum of its proper divisors (1).
111211301013103 is an equidigital number, since it uses as much as digits as its factorization.
111211301013103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 111211301013103 its reverse (301310103112111), we get a palindrome (412521404125214).
The spelling of 111211301013103 in words is "one hundred eleven trillion, two hundred eleven billion, three hundred one million, thirteen thousand, one hundred three".
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