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11121210143 is a prime number
BaseRepresentation
bin10100101101110000…
…00011001100011111
31001201001112000021222
422112320003030133
5140234012211033
65035314043555
7542410504121
oct122670031437
931631460258
1011121210143
1147976a686a
1221a45795bb
131083086324
14777023211
15451533598
hex296e0331f

11121210143 has 2 divisors, whose sum is σ = 11121210144. Its totient is φ = 11121210142.

The previous prime is 11121210097. The next prime is 11121210151. The reversal of 11121210143 is 34101212111.

11121210143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34101212111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11121210143 - 232 = 6826242847 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11121210193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560605071 + 5560605072.

It is an arithmetic number, because the mean of its divisors is an integer number (5560605072).

Almost surely, 211121210143 is an apocalyptic number.

11121210143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121210143 is an equidigital number, since it uses as much as digits as its factorization.

11121210143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11121210143 its reverse (34101212111), we get a palindrome (45222422254).

The spelling of 11121210143 in words is "eleven billion, one hundred twenty-one million, two hundred ten thousand, one hundred forty-three".