Base | Representation |
---|---|
bin | 1010000111010101101111… |
… | …1101101010100010001011 |
3 | 1110101011210110201022011002 |
4 | 2201311123331222202023 |
5 | 2424202221041033003 |
6 | 35353003111325215 |
7 | 2225324013440234 |
oct | 241653375524213 |
9 | 43334713638132 |
10 | 11121213221003 |
11 | 35a8530a2aa16 |
12 | 12b744798080b |
13 | 628958a81572 |
14 | 2a63aba9008b |
15 | 14444ce0ca88 |
hex | a1d5bf6a88b |
11121213221003 has 2 divisors, whose sum is σ = 11121213221004. Its totient is φ = 11121213221002.
The previous prime is 11121213220993. The next prime is 11121213221023. The reversal of 11121213221003 is 30012231212111.
It is an a-pointer prime, because the next prime (11121213221023) can be obtained adding 11121213221003 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11121213221003 - 24 = 11121213220987 is a prime.
It is not a weakly prime, because it can be changed into another prime (11121213221023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560606610501 + 5560606610502.
It is an arithmetic number, because the mean of its divisors is an integer number (5560606610502).
Almost surely, 211121213221003 is an apocalyptic number.
11121213221003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121213221003 is an equidigital number, since it uses as much as digits as its factorization.
11121213221003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11121213221003 its reverse (30012231212111), we get a palindrome (41133444433114).
The spelling of 11121213221003 in words is "eleven trillion, one hundred twenty-one billion, two hundred thirteen million, two hundred twenty-one thousand, three".
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