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11121232029997 is a prime number
BaseRepresentation
bin1010000111010101110100…
…0101011010100100101101
31110101011211210002220020111
42201311131011122210231
52424202240344424442
635353005022420021
72225324332346035
oct241653505324455
943334753086214
1011121232029997
1135a8540607441
1212b7452131611
1362895c93884b
142a63b03888c5
1514444e8c5b17
hexa1d5d15a92d

11121232029997 has 2 divisors, whose sum is σ = 11121232029998. Its totient is φ = 11121232029996.

The previous prime is 11121232029883. The next prime is 11121232030057. The reversal of 11121232029997 is 79992023212111.

11121232029997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7432569923076 + 3688662106921 = 2726274^2 + 1920589^2 .

It is a cyclic number.

It is not a de Polignac number, because 11121232029997 - 227 = 11121097812269 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11121232029997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11121232029097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560616014998 + 5560616014999.

It is an arithmetic number, because the mean of its divisors is an integer number (5560616014999).

Almost surely, 211121232029997 is an apocalyptic number.

It is an amenable number.

11121232029997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121232029997 is an equidigital number, since it uses as much as digits as its factorization.

11121232029997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 244944, while the sum is 49.

The spelling of 11121232029997 in words is "eleven trillion, one hundred twenty-one billion, two hundred thirty-two million, twenty-nine thousand, nine hundred ninety-seven".