Base | Representation |
---|---|
bin | 11001010010010111010010… |
… | …000010010111101011010001 |
3 | 112120202212110222212010111121 |
4 | 121102113102002113223101 |
5 | 104034103423140010303 |
6 | 1032310333124442241 |
7 | 32265611406614161 |
oct | 3122272202275321 |
9 | 476685428763447 |
10 | 111213112031953 |
11 | 32488241470a28 |
12 | 10581a1a249381 |
13 | 4a09475225049 |
14 | 1d66a59a385a1 |
15 | cccd955ce9bd |
hex | 6525d2097ad1 |
111213112031953 has 2 divisors, whose sum is σ = 111213112031954. Its totient is φ = 111213112031952.
The previous prime is 111213112031947. The next prime is 111213112032023. The reversal of 111213112031953 is 359130211312111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83399122465344 + 27813989566609 = 9132312^2 + 5273897^2 .
It is a cyclic number.
It is not a de Polignac number, because 111213112031953 - 225 = 111213078477521 is a prime.
It is not a weakly prime, because it can be changed into another prime (111213112035953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606556015976 + 55606556015977.
It is an arithmetic number, because the mean of its divisors is an integer number (55606556015977).
Almost surely, 2111213112031953 is an apocalyptic number.
It is an amenable number.
111213112031953 is a deficient number, since it is larger than the sum of its proper divisors (1).
111213112031953 is an equidigital number, since it uses as much as digits as its factorization.
111213112031953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 34.
The spelling of 111213112031953 in words is "one hundred eleven trillion, two hundred thirteen billion, one hundred twelve million, thirty-one thousand, nine hundred fifty-three".
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