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11121320023333 = 1321979351112487
BaseRepresentation
bin1010000111010110001001…
…0101000101010100100101
31110101012001220200102101221
42201311202111011110211
52424202430411221313
635353021444420341
72225326451313262
oct241654225052445
943335056612357
1011121320023333
1135a8586248103
1212b74776a76b1
13628974c37300
142a63bbd32269
151444574a7c8d
hexa1d62545525

11121320023333 has 48 divisors (see below), whose sum is σ = 12841580236800. Its totient is φ = 9598915160640.

The previous prime is 11121320023241. The next prime is 11121320023349. The reversal of 11121320023333 is 33332002312111.

It is not a de Polignac number, because 11121320023333 - 233 = 11112730088741 is a prime.

It is a super-2 number, since 2×111213200233332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11121320023298 and 11121320023307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11121320003333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 890625616 + ... + 890638102.

It is an arithmetic number, because the mean of its divisors is an integer number (267532921600).

Almost surely, 211121320023333 is an apocalyptic number.

11121320023333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11121320023333 is a deficient number, since it is larger than the sum of its proper divisors (1720260213467).

11121320023333 is a wasteful number, since it uses less digits than its factorization.

11121320023333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16122 (or 16109 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11121320023333 its reverse (33332002312111), we get a palindrome (44453322335444).

The spelling of 11121320023333 in words is "eleven trillion, one hundred twenty-one billion, three hundred twenty million, twenty-three thousand, three hundred thirty-three".

Divisors: 1 13 19 79 169 247 1027 1501 3211 3511 12487 13351 19513 45643 66709 162331 237253 253669 277369 593359 867217 986473 2110303 3084289 3605797 5270011 11273821 12824149 18742987 40095757 43841857 46875361 68510143 166713937 243658831 569944141 832995283 890631859 3167564803 3463506703 7409273833 10828938679 45025587139 65806627357 140776202827 585332632807 855486155641 11121320023333