Base | Representation |
---|---|
bin | 1010000111010110001100… |
… | …0000010001000000110101 |
3 | 1110101012002200222112122011 |
4 | 2201311203000101000311 |
5 | 2424202441310442123 |
6 | 35353022531204221 |
7 | 2225326646451364 |
oct | 241654300210065 |
9 | 43335080875564 |
10 | 11121331343413 |
11 | 35a859167a045 |
12 | 12b747b446671 |
13 | 62897739b995 |
14 | 2a63bd63b7db |
15 | 144458491e0d |
hex | a1d63011035 |
11121331343413 has 2 divisors, whose sum is σ = 11121331343414. Its totient is φ = 11121331343412.
The previous prime is 11121331343387. The next prime is 11121331343501. The reversal of 11121331343413 is 31434313312111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11064950265604 + 56381077809 = 3326402^2 + 237447^2 .
It is a cyclic number.
It is not a de Polignac number, because 11121331343413 - 225 = 11121297788981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121332343413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560665671706 + 5560665671707.
It is an arithmetic number, because the mean of its divisors is an integer number (5560665671707).
Almost surely, 211121331343413 is an apocalyptic number.
It is an amenable number.
11121331343413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121331343413 is an equidigital number, since it uses as much as digits as its factorization.
11121331343413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 31.
Adding to 11121331343413 its reverse (31434313312111), we get a palindrome (42555644655524).
The spelling of 11121331343413 in words is "eleven trillion, one hundred twenty-one billion, three hundred thirty-one million, three hundred forty-three thousand, four hundred thirteen".
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