111214123214471 has 2 divisors, whose sum is σ = 111214123214472. Its totient is φ = 111214123214470.

The previous prime is 111214123214413. The next prime is 111214123214533. The reversal of 111214123214471 is 174412321412111.

It is a weak prime.

It is an emirp because it is prime and its reverse (174412321412111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111214123214471 - 2³⁴ = 111196943345287 is a prime.

It is a super-3 number, since 3×111214123214471³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111214123214771) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55607061607235 + 55607061607236.

It is an arithmetic number, because the mean of its divisors is an integer number (55607061607236).

Almost surely, 2^{111214123214471} is an apocalyptic number.

111214123214471 is a deficient number, since it is larger than the sum of its proper divisors (1).

111214123214471 is an equidigital number, since it uses as much as digits as its factorization.

111214123214471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10752, while the sum is 35.

Adding to 111214123214471 its reverse (174412321412111), we get a palindrome (285626444626582).

The spelling of 111214123214471 in words is "one hundred eleven trillion, two hundred fourteen billion, one hundred twenty-three million, two hundred fourteen thousand, four hundred seventy-one".