Base | Representation |
---|---|
bin | 110011110010011100… |
… | …0001111001101111010 |
3 | 101122001201000011200102 |
4 | 1213210320033031322 |
5 | 3310231304130132 |
6 | 123031400435402 |
7 | 11014663336121 |
oct | 1474470171572 |
9 | 348051004612 |
10 | 111214130042 |
11 | 43190527a74 |
12 | 19679478b62 |
13 | a644bcaa52 |
14 | 5550550ab8 |
15 | 2d5d9c4c62 |
hex | 19e4e0f37a |
111214130042 has 64 divisors (see below), whose sum is σ = 178672435200. Its totient is φ = 51832535040.
The previous prime is 111214130023. The next prime is 111214130059. The reversal of 111214130042 is 240031412111.
It is a junction number, because it is equal to n+sod(n) for n = 111214129996 and 111214130023.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 96455738 + ... + 96456890.
It is an arithmetic number, because the mean of its divisors is an integer number (2791756800).
Almost surely, 2111214130042 is an apocalyptic number.
111214130042 is a deficient number, since it is larger than the sum of its proper divisors (67458305158).
111214130042 is a wasteful number, since it uses less digits than its factorization.
111214130042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1731.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 111214130042 its reverse (240031412111), we get a palindrome (351245542153).
The spelling of 111214130042 in words is "one hundred eleven billion, two hundred fourteen million, one hundred thirty thousand, forty-two".
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