Base | Representation |
---|---|
bin | 11001010010011101101101… |
… | …001100110010110010110001 |
3 | 112120210112021201222101102222 |
4 | 121102131231030302302301 |
5 | 104034212040102401431 |
6 | 1032313433424250425 |
7 | 32266244351232035 |
oct | 3122355514626261 |
9 | 476715251871388 |
10 | 111220010200241 |
11 | 32490161292958 |
12 | 10583224470a15 |
13 | 4a0a0043c5827 |
14 | 1d67111c481c5 |
15 | ccd14aed157b |
hex | 65276d332cb1 |
111220010200241 has 2 divisors, whose sum is σ = 111220010200242. Its totient is φ = 111220010200240.
The previous prime is 111220010200171. The next prime is 111220010200253. The reversal of 111220010200241 is 142002010022111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102018160963216 + 9201849237025 = 10100404^2 + 3033455^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111220010200241 is a prime.
It is not a weakly prime, because it can be changed into another prime (111220010200261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610005100120 + 55610005100121.
It is an arithmetic number, because the mean of its divisors is an integer number (55610005100121).
Almost surely, 2111220010200241 is an apocalyptic number.
It is an amenable number.
111220010200241 is a deficient number, since it is larger than the sum of its proper divisors (1).
111220010200241 is an equidigital number, since it uses as much as digits as its factorization.
111220010200241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 111220010200241 its reverse (142002010022111), we get a palindrome (253222020222352).
The spelling of 111220010200241 in words is "one hundred eleven trillion, two hundred twenty billion, ten million, two hundred thousand, two hundred forty-one".
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