Base | Representation |
---|---|
bin | 10000001011110100010… |
… | …110111000100101101111 |
3 | 10221022210012210001101021 |
4 | 100023310112320211233 |
5 | 121210242001431111 |
6 | 2210534351355011 |
7 | 143232245143063 |
oct | 20136426704557 |
9 | 3838705701337 |
10 | 1112201202031 |
11 | 399755646737 |
12 | 15b675b22a67 |
13 | 80b5982824a |
14 | 3bb8badbaa3 |
15 | 1dde6c16d71 |
hex | 102f45b896f |
1112201202031 has 2 divisors, whose sum is σ = 1112201202032. Its totient is φ = 1112201202030.
The previous prime is 1112201201987. The next prime is 1112201202037. The reversal of 1112201202031 is 1302021022111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112201202031 - 29 = 1112201201519 is a prime.
It is a super-2 number, since 2×11122012020312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1112201201996 and 1112201202014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112201202037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556100601015 + 556100601016.
It is an arithmetic number, because the mean of its divisors is an integer number (556100601016).
Almost surely, 21112201202031 is an apocalyptic number.
1112201202031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112201202031 is an equidigital number, since it uses as much as digits as its factorization.
1112201202031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1112201202031 its reverse (1302021022111), we get a palindrome (2414222224142).
The spelling of 1112201202031 in words is "one trillion, one hundred twelve billion, two hundred one million, two hundred two thousand, thirty-one".
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