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1112201301317 is a prime number
BaseRepresentation
bin10000001011110100010…
…111010000110101000101
310221022210012222002120112
4100023310113100311011
5121210242013120232
62210534353442405
7143232246035411
oct20136427206505
93838705862515
101112201301317
11399755704297
1215b675b70405
1380b598614b2
143bb8bb25d41
151dde6c364b2
hex102f45d0d45

1112201301317 has 2 divisors, whose sum is σ = 1112201301318. Its totient is φ = 1112201301316.

The previous prime is 1112201301301. The next prime is 1112201301413. The reversal of 1112201301317 is 7131031022111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 807816273796 + 304385027521 = 898786^2 + 551711^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112201301317 - 24 = 1112201301301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112201301292 and 1112201301301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112201301017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556100650658 + 556100650659.

It is an arithmetic number, because the mean of its divisors is an integer number (556100650659).

Almost surely, 21112201301317 is an apocalyptic number.

It is an amenable number.

1112201301317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112201301317 is an equidigital number, since it uses as much as digits as its factorization.

1112201301317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 1112201301317 its reverse (7131031022111), we get a palindrome (8243232323428).

The spelling of 1112201301317 in words is "one trillion, one hundred twelve billion, two hundred one million, three hundred one thousand, three hundred seventeen".