Base | Representation |
---|---|
bin | 10000001011110100111… |
… | …100010011011001100101 |
3 | 10221022210220020101222211 |
4 | 100023310330103121211 |
5 | 121210302004324143 |
6 | 2210535341523421 |
7 | 143232424416133 |
oct | 20136474233145 |
9 | 3838726211884 |
10 | 1112211011173 |
11 | 399760136469 |
12 | 15b679273571 |
13 | 80b5b880c82 |
14 | 3bb8d132753 |
15 | 1dde7a0349d |
hex | 102f4f13665 |
1112211011173 has 2 divisors, whose sum is σ = 1112211011174. Its totient is φ = 1112211011172.
The previous prime is 1112211011167. The next prime is 1112211011189. The reversal of 1112211011173 is 3711101122111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1105816290084 + 6394721089 = 1051578^2 + 79967^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112211011173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112211011473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556105505586 + 556105505587.
It is an arithmetic number, because the mean of its divisors is an integer number (556105505587).
Almost surely, 21112211011173 is an apocalyptic number.
It is an amenable number.
1112211011173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112211011173 is an equidigital number, since it uses as much as digits as its factorization.
1112211011173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 22.
Adding to 1112211011173 its reverse (3711101122111), we get a palindrome (4823312133284).
The spelling of 1112211011173 in words is "one trillion, one hundred twelve billion, two hundred eleven million, eleven thousand, one hundred seventy-three".
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