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11122111323047 is a prime number
BaseRepresentation
bin1010000111011001000101…
…1111101001101110100111
31110101021010001122121112202
42201312101133221232213
52424211040444314142
635353232153005115
72225355200252444
oct241662137515647
943337101577482
1011122111323047
1135a895198630a
1212b76586b379b
13628a6cb620aa
142a64550749cb
151444a1bb2032
hexa1d917e9ba7

11122111323047 has 2 divisors, whose sum is σ = 11122111323048. Its totient is φ = 11122111323046.

The previous prime is 11122111322977. The next prime is 11122111323107. The reversal of 11122111323047 is 74032311122111.

It is a strong prime.

It is an emirp because it is prime and its reverse (74032311122111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11122111323047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11122111326047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561055661523 + 5561055661524.

It is an arithmetic number, because the mean of its divisors is an integer number (5561055661524).

Almost surely, 211122111323047 is an apocalyptic number.

11122111323047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122111323047 is an equidigital number, since it uses as much as digits as its factorization.

11122111323047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 11122111323047 its reverse (74032311122111), we get a palindrome (85154422445158).

The spelling of 11122111323047 in words is "eleven trillion, one hundred twenty-two billion, one hundred eleven million, three hundred twenty-three thousand, forty-seven".