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111221201023102 = 255610600511551
BaseRepresentation
bin11001010010011110110100…
…001011011011000001111110
3112120210122100201201110022101
4121102132310023123001332
5104034222004430214402
61032314151523535314
732266316021115562
oct3122366413330176
9476718321643271
10111221201023102
11324907124a0785
12105834b722a53a
134a0a164025b41
141d671c60696a2
15ccd1ba807b87
hex6527b42db07e

111221201023102 has 4 divisors (see below), whose sum is σ = 166831801534656. Its totient is φ = 55610600511550.

The previous prime is 111221201023087. The next prime is 111221201023123. The reversal of 111221201023102 is 201320102122111.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 111221201023102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27805300255774 + ... + 27805300255777.

It is an arithmetic number, because the mean of its divisors is an integer number (41707950383664).

Almost surely, 2111221201023102 is an apocalyptic number.

111221201023102 is a deficient number, since it is larger than the sum of its proper divisors (55610600511554).

111221201023102 is an equidigital number, since it uses as much as digits as its factorization.

111221201023102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55610600511553.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 111221201023102 its reverse (201320102122111), we get a palindrome (312541303145213).

The spelling of 111221201023102 in words is "one hundred eleven trillion, two hundred twenty-one billion, two hundred one million, twenty-three thousand, one hundred two".

Divisors: 1 2 55610600511551 111221201023102