Base | Representation |
---|---|
bin | 10000001011110101011… |
… | …110100011000110000001 |
3 | 10221022211112010111100222 |
4 | 100023311132203012001 |
5 | 121210311304111403 |
6 | 2210540302152425 |
7 | 143232563625515 |
oct | 20136536430601 |
9 | 3838745114328 |
10 | 1112219988353 |
11 | 399765208121 |
12 | 15b680282715 |
13 | 80b606a5106 |
14 | 3bb903cc145 |
15 | 1dde86c8338 |
hex | 102f57a3181 |
1112219988353 has 2 divisors, whose sum is σ = 1112219988354. Its totient is φ = 1112219988352.
The previous prime is 1112219988329. The next prime is 1112219988367. The reversal of 1112219988353 is 3538899122111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1107446836609 + 4773151744 = 1052353^2 + 69088^2 .
It is a cyclic number.
It is not a de Polignac number, because 1112219988353 - 28 = 1112219988097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1112219988295 and 1112219988304.
It is not a weakly prime, because it can be changed into another prime (1112219988853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556109994176 + 556109994177.
It is an arithmetic number, because the mean of its divisors is an integer number (556109994177).
Almost surely, 21112219988353 is an apocalyptic number.
It is an amenable number.
1112219988353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112219988353 is an equidigital number, since it uses as much as digits as its factorization.
1112219988353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 933120, while the sum is 53.
The spelling of 1112219988353 in words is "one trillion, one hundred twelve billion, two hundred nineteen million, nine hundred eighty-eight thousand, three hundred fifty-three".
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