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111222011109983 is a prime number
BaseRepresentation
bin11001010010011111100100…
…011101101010001001011111
3112120210201110012001010121012
4121102133210131222021133
5104034230134321004413
61032314404142525435
732266345055543114
oct3122374435521137
9476721405033535
10111222011109983
1132490a987a0a74
12105836a259687b
134a0a262acaca7
141d6726189c90b
15ccd2169c37a8
hex6527e476a25f

111222011109983 has 2 divisors, whose sum is σ = 111222011109984. Its totient is φ = 111222011109982.

The previous prime is 111222011109967. The next prime is 111222011110051. The reversal of 111222011109983 is 389901110222111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 111222011109983 - 24 = 111222011109967 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111222011109983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111222011109283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55611005554991 + 55611005554992.

It is an arithmetic number, because the mean of its divisors is an integer number (55611005554992).

Almost surely, 2111222011109983 is an apocalyptic number.

111222011109983 is a deficient number, since it is larger than the sum of its proper divisors (1).

111222011109983 is an equidigital number, since it uses as much as digits as its factorization.

111222011109983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 41.

The spelling of 111222011109983 in words is "one hundred eleven trillion, two hundred twenty-two billion, eleven million, one hundred nine thousand, nine hundred eighty-three".