Base | Representation |
---|---|
bin | 110011110010101011… |
… | …0101110001010101101 |
3 | 101122002021001011101202 |
4 | 1213211112232022231 |
5 | 3310240330334013 |
6 | 123032244015245 |
7 | 11015121300554 |
oct | 1474526561255 |
9 | 348067034352 |
10 | 111222121133 |
11 | 43194a95882 |
12 | 19680091525 |
13 | a6467680c6 |
14 | 5551630d9b |
15 | 2d5e552858 |
hex | 19e55ae2ad |
111222121133 has 2 divisors, whose sum is σ = 111222121134. Its totient is φ = 111222121132.
The previous prime is 111222121081. The next prime is 111222121139. The reversal of 111222121133 is 331121222111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86681958724 + 24540162409 = 294418^2 + 156653^2 .
It is an emirp because it is prime and its reverse (331121222111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111222121133 - 218 = 111221858989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111222121139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55611060566 + 55611060567.
It is an arithmetic number, because the mean of its divisors is an integer number (55611060567).
Almost surely, 2111222121133 is an apocalyptic number.
It is an amenable number.
111222121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
111222121133 is an equidigital number, since it uses as much as digits as its factorization.
111222121133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 20.
Adding to 111222121133 its reverse (331121222111), we get a palindrome (442343343244).
The spelling of 111222121133 in words is "one hundred eleven billion, two hundred twenty-two million, one hundred twenty-one thousand, one hundred thirty-three".
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