Base | Representation |
---|---|
bin | 1010000111011010011000… |
… | …0000010100101100110011 |
3 | 1110101022000001011011021022 |
4 | 2201312212000110230303 |
5 | 2424212242042310422 |
6 | 35353330244250055 |
7 | 2225366546162504 |
oct | 241664600245463 |
9 | 43338001134238 |
10 | 11122455431987 |
11 | 35a9009147469 |
12 | 12b77339a092b |
13 | 628ac6234a53 |
14 | 2a6488a4abab |
15 | 1444c1ed5342 |
hex | a1da6014b33 |
11122455431987 has 2 divisors, whose sum is σ = 11122455431988. Its totient is φ = 11122455431986.
The previous prime is 11122455431981. The next prime is 11122455432041. The reversal of 11122455431987 is 78913455422111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11122455431987 - 242 = 6724408920883 is a prime.
It is not a weakly prime, because it can be changed into another prime (11122455431981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561227715993 + 5561227715994.
It is an arithmetic number, because the mean of its divisors is an integer number (5561227715994).
Almost surely, 211122455431987 is an apocalyptic number.
11122455431987 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122455431987 is an equidigital number, since it uses as much as digits as its factorization.
11122455431987 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2419200, while the sum is 53.
The spelling of 11122455431987 in words is "eleven trillion, one hundred twenty-two billion, four hundred fifty-five million, four hundred thirty-one thousand, nine hundred eighty-seven".
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