11123000113 has 2 divisors, whose sum is σ = 11123000114. Its totient is φ = 11123000112.

The previous prime is 11123000111. The next prime is 11123000149. The reversal of 11123000113 is 31100032111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10886209569 + 236790544 = 104337^2 + 15388^2 .

It is a cyclic number.

It is not a de Polignac number, because 11123000113 - 2¹ = 11123000111 is a prime.

It is a super-2 number, since 2×11123000113² (a number of 21 digits) contains 22 as substring.

Together with 11123000111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11123000093 and 11123000102.

It is not a weakly prime, because it can be changed into another prime (11123000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561500056 + 5561500057.

It is an arithmetic number, because the mean of its divisors is an integer number (5561500057).

Almost surely, 2^11123000113 is an apocalyptic number.

It is an amenable number.

11123000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11123000113 is an equidigital number, since it uses as much as digits as its factorization.

11123000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11123000113 its reverse (31100032111), we get a palindrome (42223032224).

The spelling of 11123000113 in words is "eleven billion, one hundred twenty-three million, one hundred thirteen", and thus it is an aban number.