Base | Representation |
---|---|
bin | 110011110010111010… |
… | …1111111111000001101 |
3 | 101122002211110201022201 |
4 | 1213211311333320031 |
5 | 3310244430221031 |
6 | 123033135441501 |
7 | 11015251056433 |
oct | 1474565777015 |
9 | 348084421281 |
10 | 111230320141 |
11 | 43199685916 |
12 | 19682986291 |
13 | a648378ca5 |
14 | 5552766d53 |
15 | 2d60121d61 |
hex | 19e5d7fe0d |
111230320141 has 2 divisors, whose sum is σ = 111230320142. Its totient is φ = 111230320140.
The previous prime is 111230320129. The next prime is 111230320147. The reversal of 111230320141 is 141023032111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75226775625 + 36003544516 = 274275^2 + 189746^2 .
It is a cyclic number.
It is not a de Polignac number, because 111230320141 - 25 = 111230320109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111230320147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55615160070 + 55615160071.
It is an arithmetic number, because the mean of its divisors is an integer number (55615160071).
Almost surely, 2111230320141 is an apocalyptic number.
It is an amenable number.
111230320141 is a deficient number, since it is larger than the sum of its proper divisors (1).
111230320141 is an equidigital number, since it uses as much as digits as its factorization.
111230320141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 111230320141 its reverse (141023032111), we get a palindrome (252253352252).
The spelling of 111230320141 in words is "one hundred eleven billion, two hundred thirty million, three hundred twenty thousand, one hundred forty-one".
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