Base | Representation |
---|---|
bin | 110011110010111110… |
… | …1001011000101100001 |
3 | 101122002222000021110021 |
4 | 1213211331023011201 |
5 | 3310300420413212 |
6 | 123033244033441 |
7 | 11015303052235 |
oct | 1474575130541 |
9 | 348088007407 |
10 | 111232201057 |
11 | 4319a74aa9a |
12 | 19683532881 |
13 | a648887163 |
14 | 5552ad65c5 |
15 | 2d60394307 |
hex | 19e5f4b161 |
111232201057 has 2 divisors, whose sum is σ = 111232201058. Its totient is φ = 111232201056.
The previous prime is 111232201009. The next prime is 111232201063. The reversal of 111232201057 is 750102232111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101588175441 + 9644025616 = 318729^2 + 98204^2 .
It is an emirp because it is prime and its reverse (750102232111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111232201057 - 223 = 111223812449 is a prime.
It is not a weakly prime, because it can be changed into another prime (111232201757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55616100528 + 55616100529.
It is an arithmetic number, because the mean of its divisors is an integer number (55616100529).
Almost surely, 2111232201057 is an apocalyptic number.
It is an amenable number.
111232201057 is a deficient number, since it is larger than the sum of its proper divisors (1).
111232201057 is an equidigital number, since it uses as much as digits as its factorization.
111232201057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 111232201057 its reverse (750102232111), we get a palindrome (861334433168).
The spelling of 111232201057 in words is "one hundred eleven billion, two hundred thirty-two million, two hundred one thousand, fifty-seven".
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