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1112322313147 is a prime number
BaseRepresentation
bin10000001011111011100…
…100111000101110111011
310221100002122200010121011
4100023323210320232323
5121211014003010042
62210554355254351
7143235245442523
oct20137344705673
93840078603534
101112322313147
11399807a47271
1215b6aa5aa3b7
1380b78950b26
143bb9dc26683
151de0268ba17
hex102fb938bbb

1112322313147 has 2 divisors, whose sum is σ = 1112322313148. Its totient is φ = 1112322313146.

The previous prime is 1112322313121. The next prime is 1112322313187. The reversal of 1112322313147 is 7413132232111.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (7413132232111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1112322313147 - 215 = 1112322280379 is a prime.

It is not a weakly prime, because it can be changed into another prime (1112322313187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556161156573 + 556161156574.

It is an arithmetic number, because the mean of its divisors is an integer number (556161156574).

Almost surely, 21112322313147 is an apocalyptic number.

1112322313147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112322313147 is an equidigital number, since it uses as much as digits as its factorization.

1112322313147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048, while the sum is 31.

Adding to 1112322313147 its reverse (7413132232111), we get a palindrome (8525454545258).

The spelling of 1112322313147 in words is "one trillion, one hundred twelve billion, three hundred twenty-two million, three hundred thirteen thousand, one hundred forty-seven".