Base | Representation |
---|---|
bin | 11001010010101001001100… |
… | …001111011010010011100110 |
3 | 112120211201010011200211201112 |
4 | 121102221030033122103212 |
5 | 104034412314041441014 |
6 | 1032323233232425022 |
7 | 32300162063053415 |
oct | 3122511417322346 |
9 | 476751104624645 |
10 | 111232342140134 |
11 | 3249540a353916 |
12 | 105856a63a8172 |
13 | 4a0b21b25c097 |
14 | 1d6796199147c |
15 | ccd61d96e73e |
hex | 652a4c3da4e6 |
111232342140134 has 4 divisors (see below), whose sum is σ = 166848513210204. Its totient is φ = 55616171070066.
The previous prime is 111232342140091. The next prime is 111232342140163. The reversal of 111232342140134 is 431041243232111.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 111232342140134.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27808085535032 + ... + 27808085535035.
It is an arithmetic number, because the mean of its divisors is an integer number (41712128302551).
Almost surely, 2111232342140134 is an apocalyptic number.
111232342140134 is a deficient number, since it is larger than the sum of its proper divisors (55616171070070).
111232342140134 is an equidigital number, since it uses as much as digits as its factorization.
111232342140134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55616171070069.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 111232342140134 its reverse (431041243232111), we get a palindrome (542273585372245).
The spelling of 111232342140134 in words is "one hundred eleven trillion, two hundred thirty-two billion, three hundred forty-two million, one hundred forty thousand, one hundred thirty-four".
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