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11123324437 is a prime number
BaseRepresentation
bin10100101110000000…
…00111011000010101
31001201012111102120011
422113000013120111
5140240032340222
65035431240221
7542434461211
oct122700073025
931635442504
1011123324437
114798910315
1221a5219071
1310836467a4
14777413941
154517eec77
hex297007615

11123324437 has 2 divisors, whose sum is σ = 11123324438. Its totient is φ = 11123324436.

The previous prime is 11123324371. The next prime is 11123324449. The reversal of 11123324437 is 73442332111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9621451921 + 1501872516 = 98089^2 + 38754^2 .

It is a cyclic number.

It is not a de Polignac number, because 11123324437 - 223 = 11114935829 is a prime.

It is a super-2 number, since 2×111233244372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11123324399 and 11123324408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11123334437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561662218 + 5561662219.

It is an arithmetic number, because the mean of its divisors is an integer number (5561662219).

Almost surely, 211123324437 is an apocalyptic number.

It is an amenable number.

11123324437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11123324437 is an equidigital number, since it uses as much as digits as its factorization.

11123324437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12096, while the sum is 31.

Adding to 11123324437 its reverse (73442332111), we get a palindrome (84565656548).

The spelling of 11123324437 in words is "eleven billion, one hundred twenty-three million, three hundred twenty-four thousand, four hundred thirty-seven".