1112413134132 has 144 divisors (see below), whose sum is σ = 2932089189120. Its totient is φ = 355362868224.

The previous prime is 1112413134113. The next prime is 1112413134149. The reversal of 1112413134132 is 2314313142111.

1112413134132 is a `hidden beast` number, since 1 + 1 + 1 + 241 + 3 + 1 + 3 + 413 + 2 = 666.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 1112413134096 and 1112413134105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17136328 + ... + 17201120.

It is an arithmetic number, because the mean of its divisors is an integer number (20361730480).

Almost surely, 2^{1112413134132} is an apocalyptic number.

1112413134132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1112413134132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1466044594560).

1112413134132 is an abundant number, since it is smaller than the sum of its proper divisors (1819676054988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1112413134132 is a wasteful number, since it uses less digits than its factorization.

1112413134132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65062 (or 65057 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 1112413134132 its reverse (2314313142111), we get a palindrome (3426726276243).

The spelling of 1112413134132 in words is "one trillion, one hundred twelve billion, four hundred thirteen million, one hundred thirty-four thousand, one hundred thirty-two".