111243234130493 has 2 divisors, whose sum is σ = 111243234130494. Its totient is φ = 111243234130492.

The previous prime is 111243234130411. The next prime is 111243234130517. The reversal of 111243234130493 is 394031432342111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111069214167844 + 174019962649 = 10538938^2 + 417157^2 .

It is a cyclic number.

It is not a de Polignac number, because 111243234130493 - 2³² = 111238939163197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111243234130493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111243234138493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621617065246 + 55621617065247.

It is an arithmetic number, because the mean of its divisors is an integer number (55621617065247).

Almost surely, 2^{111243234130493} is an apocalyptic number.

It is an amenable number.

111243234130493 is a deficient number, since it is larger than the sum of its proper divisors (1).

111243234130493 is an equidigital number, since it uses as much as digits as its factorization.

111243234130493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 41.

The spelling of 111243234130493 in words is "one hundred eleven trillion, two hundred forty-three billion, two hundred thirty-four million, one hundred thirty thousand, four hundred ninety-three".