Base | Representation |
---|---|
bin | 11001010010110011010101… |
… | …011101000100100110001011 |
3 | 112120212202020020220110221222 |
4 | 121102303111131010212023 |
5 | 104040102120414300121 |
6 | 1032332234121552255 |
7 | 32301026021351651 |
oct | 3122632535044613 |
9 | 476782206813858 |
10 | 111243234134411 |
11 | 32499a99622385 |
12 | 1058782604568b |
13 | 4a0c26599c002 |
14 | 1d682b6388dd1 |
15 | ccda59cc70ab |
hex | 652cd574498b |
111243234134411 has 2 divisors, whose sum is σ = 111243234134412. Its totient is φ = 111243234134410.
The previous prime is 111243234134381. The next prime is 111243234134413. The reversal of 111243234134411 is 114431432342111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111243234134411 - 238 = 110968356227467 is a prime.
Together with 111243234134413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111243234134413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621617067205 + 55621617067206.
It is an arithmetic number, because the mean of its divisors is an integer number (55621617067206).
Almost surely, 2111243234134411 is an apocalyptic number.
111243234134411 is a deficient number, since it is larger than the sum of its proper divisors (1).
111243234134411 is an equidigital number, since it uses as much as digits as its factorization.
111243234134411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27648, while the sum is 35.
Adding to 111243234134411 its reverse (114431432342111), we get a palindrome (225674666476522).
The spelling of 111243234134411 in words is "one hundred eleven trillion, two hundred forty-three billion, two hundred thirty-four million, one hundred thirty-four thousand, four hundred eleven".
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