111243330031 has 2 divisors, whose sum is σ = 111243330032. Its totient is φ = 111243330030.

The previous prime is 111243329999. The next prime is 111243330059. The reversal of 111243330031 is 130033342111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111243330031 - 2⁵ = 111243329999 is a prime.

It is a super-2 number, since 2×111243330031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111243329984 and 111243330011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111243330631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621665015 + 55621665016.

It is an arithmetic number, because the mean of its divisors is an integer number (55621665016).

Almost surely, 2^111243330031 is an apocalyptic number.

111243330031 is a deficient number, since it is larger than the sum of its proper divisors (1).

111243330031 is an equidigital number, since it uses as much as digits as its factorization.

111243330031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 111243330031 its reverse (130033342111), we get a palindrome (241276672142).

The spelling of 111243330031 in words is "one hundred eleven billion, two hundred forty-three million, three hundred thirty thousand, thirty-one".