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111243334224002 = 2125968927640957
BaseRepresentation
bin11001010010110011011011…
…011010111000100010000010
3112120212202111020020120001212
4121102303123122320202002
5104040102322030132002
61032332252055130122
732301031345166231
oct3122633332704202
9476782436216055
10111243334224002
113249a040075152
1210587853673942
134a0c280644516
141d682c57a0b18
15ccda63998352
hex652cdb6b8882

111243334224002 has 16 divisors (see below), whose sum is σ = 167000222430720. Its totient is φ = 55576594836048.

The previous prime is 111243334223929. The next prime is 111243334224017. The reversal of 111243334224002 is 200422433342111.

It is a happy number.

It is a super-3 number, since 3×1112433342240023 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 111243334224002.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173237708 + ... + 173878664.

It is an arithmetic number, because the mean of its divisors is an integer number (10437513901920).

Almost surely, 2111243334224002 is an apocalyptic number.

111243334224002 is a deficient number, since it is larger than the sum of its proper divisors (55756888206718).

111243334224002 is a wasteful number, since it uses less digits than its factorization.

111243334224002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 711145.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 111243334224002 its reverse (200422433342111), we get a palindrome (311665767566113).

The spelling of 111243334224002 in words is "one hundred eleven trillion, two hundred forty-three billion, three hundred thirty-four million, two hundred twenty-four thousand, two".

Divisors: 1 2 1259 2518 68927 137854 640957 1281914 86779093 173558186 806964863 1613929726 44179243139 88358486278 55621667112001 111243334224002