Base | Representation |
---|---|
bin | 10000001100000100100… |
… | …001000000100001001111 |
3 | 10221100111002212211002112 |
4 | 100030010201000201033 |
5 | 121211320401311112 |
6 | 2211021314014235 |
7 | 143242046312111 |
oct | 20140441004117 |
9 | 3840432784075 |
10 | 1112472291407 |
11 | 399884674144 |
12 | 15b73087737b |
13 | 80ba0a42b69 |
14 | 3bbb5b073b1 |
15 | 1de10914a22 |
hex | 1030484084f |
1112472291407 has 2 divisors, whose sum is σ = 1112472291408. Its totient is φ = 1112472291406.
The previous prime is 1112472291347. The next prime is 1112472291449. The reversal of 1112472291407 is 7041922742111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112472291407 - 216 = 1112472225871 is a prime.
It is a super-4 number, since 4×11124722914074 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112472291467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556236145703 + 556236145704.
It is an arithmetic number, because the mean of its divisors is an integer number (556236145704).
Almost surely, 21112472291407 is an apocalyptic number.
1112472291407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112472291407 is an equidigital number, since it uses as much as digits as its factorization.
1112472291407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56448, while the sum is 41.
The spelling of 1112472291407 in words is "one trillion, one hundred twelve billion, four hundred seventy-two million, two hundred ninety-one thousand, four hundred seven".
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