Base | Representation |
---|---|
bin | 10100101110001110… |
… | …11100111001110011 |
3 | 1001201100010010122112 |
4 | 22113013130321303 |
5 | 140241030410403 |
6 | 5035540355535 |
7 | 542460021131 |
oct | 122707347163 |
9 | 31640103575 |
10 | 11125247603 |
11 | 4799a04208 |
12 | 21a59a5bab |
13 | 1083b6ac62 |
14 | 777794751 |
15 | 451a7e9d8 |
hex | 2971dce73 |
11125247603 has 2 divisors, whose sum is σ = 11125247604. Its totient is φ = 11125247602.
The previous prime is 11125247599. The next prime is 11125247611. The reversal of 11125247603 is 30674252111.
It is a weak prime.
It is an emirp because it is prime and its reverse (30674252111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11125247603 - 22 = 11125247599 is a prime.
It is a super-2 number, since 2×111252476032 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11125247603.
It is not a weakly prime, because it can be changed into another prime (11125247663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562623801 + 5562623802.
It is an arithmetic number, because the mean of its divisors is an integer number (5562623802).
Almost surely, 211125247603 is an apocalyptic number.
11125247603 is a deficient number, since it is larger than the sum of its proper divisors (1).
11125247603 is an equidigital number, since it uses as much as digits as its factorization.
11125247603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 11125247603 its reverse (30674252111), we get a palindrome (41799499714).
The spelling of 11125247603 in words is "eleven billion, one hundred twenty-five million, two hundred forty-seven thousand, six hundred three".
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