Base | Representation |
---|---|
bin | 10000001100001000001… |
… | …100011111000000011001 |
3 | 10221100122102000221222012 |
4 | 100030020030133000121 |
5 | 121211432202120441 |
6 | 2211031401035305 |
7 | 143243426066156 |
oct | 20141014370031 |
9 | 3840572027865 |
10 | 1112534020121 |
11 | 3999064a5907 |
12 | 15b749485b35 |
13 | 80bb0776924 |
14 | 3bbbddb522d |
15 | 1de160599eb |
hex | 1030831f019 |
1112534020121 has 2 divisors, whose sum is σ = 1112534020122. Its totient is φ = 1112534020120.
The previous prime is 1112534020099. The next prime is 1112534020123. The reversal of 1112534020121 is 1210204352111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1111348182025 + 1185838096 = 1054205^2 + 34436^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112534020121 is a prime.
Together with 1112534020123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1112534020123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556267010060 + 556267010061.
It is an arithmetic number, because the mean of its divisors is an integer number (556267010061).
Almost surely, 21112534020121 is an apocalyptic number.
It is an amenable number.
1112534020121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112534020121 is an equidigital number, since it uses as much as digits as its factorization.
1112534020121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 1112534020121 its reverse (1210204352111), we get a palindrome (2322738372232).
The spelling of 1112534020121 in words is "one trillion, one hundred twelve billion, five hundred thirty-four million, twenty thousand, one hundred twenty-one".
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