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1112555722241 is a prime number
BaseRepresentation
bin10000001100001001011…
…111010001011000000001
310221100200220212112200102
4100030021133101120001
5121212003231102431
62211033454132145
7143244111414515
oct20141137213001
93840626775612
101112555722241
11399917778a47
1215b7547b1055
1380bb5104a12
143bbc2c24145
151de17de4dcb
hex103097d1601

1112555722241 has 2 divisors, whose sum is σ = 1112555722242. Its totient is φ = 1112555722240.

The previous prime is 1112555722189. The next prime is 1112555722247. The reversal of 1112555722241 is 1422275552111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 643330722241 + 469225000000 = 802079^2 + 685000^2 .

It is an emirp because it is prime and its reverse (1422275552111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1112555722241 - 26 = 1112555722177 is a prime.

It is a super-3 number, since 3×11125557222413 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1112555722195 and 1112555722204.

It is not a weakly prime, because it can be changed into another prime (1112555722247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556277861120 + 556277861121.

It is an arithmetic number, because the mean of its divisors is an integer number (556277861121).

Almost surely, 21112555722241 is an apocalyptic number.

It is an amenable number.

1112555722241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112555722241 is an equidigital number, since it uses as much as digits as its factorization.

1112555722241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 56000, while the sum is 38.

The spelling of 1112555722241 in words is "one trillion, one hundred twelve billion, five hundred fifty-five million, seven hundred twenty-two thousand, two hundred forty-one".