Base | Representation |
---|---|
bin | 10000001100001110000… |
… | …010011001111010101101 |
3 | 10221100220020110221112001 |
4 | 100030032002121322231 |
5 | 121212132300304013 |
6 | 2211045222012301 |
7 | 143246026206544 |
oct | 20141602317255 |
9 | 3840806427461 |
10 | 1112632041133 |
11 | 399956865508 |
12 | 15b776277091 |
13 | 80bc7b76722 |
14 | 3bbcd00d15b |
15 | 1de1e96cddd |
hex | 1030e099ead |
1112632041133 has 2 divisors, whose sum is σ = 1112632041134. Its totient is φ = 1112632041132.
The previous prime is 1112632041127. The next prime is 1112632041173. The reversal of 1112632041133 is 3311402362111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 622076083524 + 490555957609 = 788718^2 + 700397^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112632041133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1112632041173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556316020566 + 556316020567.
It is an arithmetic number, because the mean of its divisors is an integer number (556316020567).
Almost surely, 21112632041133 is an apocalyptic number.
It is an amenable number.
1112632041133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112632041133 is an equidigital number, since it uses as much as digits as its factorization.
1112632041133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 1112632041133 in words is "one trillion, one hundred twelve billion, six hundred thirty-two million, forty-one thousand, one hundred thirty-three".
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