Base | Representation |
---|---|
bin | 10000001100100100000… |
… | …101101011111110110111 |
3 | 10221101212000121211002211 |
4 | 100030210011223332313 |
5 | 121213412003002221 |
6 | 2211150035314251 |
7 | 143261140622665 |
oct | 20144405537667 |
9 | 3841760554084 |
10 | 1113002000311 |
11 | 39a0266822a3 |
12 | 15b85a14b987 |
13 | 80c566ca596 |
14 | 3bc261d3c35 |
15 | 1de4219a6e1 |
hex | 1032416bfb7 |
1113002000311 has 2 divisors, whose sum is σ = 1113002000312. Its totient is φ = 1113002000310.
The previous prime is 1113002000303. The next prime is 1113002000321. The reversal of 1113002000311 is 1130002003111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113002000311 - 23 = 1113002000303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113002000291 and 1113002000300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113002000321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556501000155 + 556501000156.
It is an arithmetic number, because the mean of its divisors is an integer number (556501000156).
Almost surely, 21113002000311 is an apocalyptic number.
1113002000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113002000311 is an equidigital number, since it uses as much as digits as its factorization.
1113002000311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1113002000311 its reverse (1130002003111), we get a palindrome (2243004003422).
The spelling of 1113002000311 in words is "one trillion, one hundred thirteen billion, two million, three hundred eleven", and thus it is an aban number.
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