Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01111000001011010 |
3 | 1001201200010122010220 |
4 | 22113121233001122 |
5 | 140243242243120 |
6 | 5040231220510 |
7 | 542545532256 |
oct | 122731570132 |
9 | 31650118126 |
10 | 11130040410 |
11 | 47a1688105 |
12 | 21a7517736 |
13 | 1084b58638 |
14 | 778281266 |
15 | 4521c9b40 |
hex | 29766f05a |
11130040410 has 16 divisors (see below), whose sum is σ = 26712097056. Its totient is φ = 2968010768.
The previous prime is 11130040409. The next prime is 11130040447. The reversal of 11130040410 is 1404003111.
It is a super-3 number, since 3×111300404103 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11130040410.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185500644 + ... + 185500703.
It is an arithmetic number, because the mean of its divisors is an integer number (1669506066).
Almost surely, 211130040410 is an apocalyptic number.
11130040410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11130040410 is an abundant number, since it is smaller than the sum of its proper divisors (15582056646).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11130040410 is a wasteful number, since it uses less digits than its factorization.
11130040410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 371001357.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11130040410 its reverse (1404003111), we get a palindrome (12534043521).
The spelling of 11130040410 in words is "eleven billion, one hundred thirty million, forty thousand, four hundred ten".
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