Base | Representation |
---|---|
bin | 110011110101000001… |
… | …1100111101101000011 |
3 | 101122021202110121212101 |
4 | 1213222003213231003 |
5 | 3310421024000003 |
6 | 123044142411231 |
7 | 11020066614244 |
oct | 1475203475503 |
9 | 348252417771 |
10 | 111301000003 |
11 | 43225570726 |
12 | 196a2590b17 |
13 | a659bc50ab |
14 | 555bcc4ccb |
15 | 2d6643411d |
hex | 19ea0e7b43 |
111301000003 has 2 divisors, whose sum is σ = 111301000004. Its totient is φ = 111301000002.
The previous prime is 111300999961. The next prime is 111301000037. The reversal of 111301000003 is 300000103111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111301000003 is a prime.
It is not a weakly prime, because it can be changed into another prime (111301040003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650500001 + 55650500002.
It is an arithmetic number, because the mean of its divisors is an integer number (55650500002).
Almost surely, 2111301000003 is an apocalyptic number.
111301000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
111301000003 is an equidigital number, since it uses as much as digits as its factorization.
111301000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 10.
Adding to 111301000003 its reverse (300000103111), we get a palindrome (411301103114).
The spelling of 111301000003 in words is "one hundred eleven billion, three hundred one million, three", and thus it is an aban number.
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