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111302100131 is a prime number
BaseRepresentation
bin110011110101000011…
…1110100010010100011
3101122021211112111221212
41213222013310102203
53310421314201011
6123044222140335
711020112145515
oct1475207642243
9348254474855
10111302100131
1143226152222
12196a2a216ab
13a65a1bba61
14555c0cdbb5
152d665a008b
hex19ea1f44a3

111302100131 has 2 divisors, whose sum is σ = 111302100132. Its totient is φ = 111302100130.

The previous prime is 111302100061. The next prime is 111302100167. The reversal of 111302100131 is 131001203111.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (131001203111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111302100131 - 214 = 111302083747 is a prime.

It is a super-2 number, since 2×1113021001312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111302120131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55651050065 + 55651050066.

It is an arithmetic number, because the mean of its divisors is an integer number (55651050066).

Almost surely, 2111302100131 is an apocalyptic number.

111302100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111302100131 is an equidigital number, since it uses as much as digits as its factorization.

111302100131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 111302100131 its reverse (131001203111), we get a palindrome (242303303242).

The spelling of 111302100131 in words is "one hundred eleven billion, three hundred two million, one hundred thousand, one hundred thirty-one".