Base | Representation |
---|---|
bin | 10100101110111010… |
… | …11110011101111111 |
3 | 1001201201222110111211 |
4 | 22113131132131333 |
5 | 140244020134213 |
6 | 5040304225251 |
7 | 542560055542 |
oct | 122735363577 |
9 | 31651873454 |
10 | 11131021183 |
11 | 47a2197a67 |
12 | 21a790b227 |
13 | 108510cb89 |
14 | 778458859 |
15 | 45232053d |
hex | 29775e77f |
11131021183 has 2 divisors, whose sum is σ = 11131021184. Its totient is φ = 11131021182.
The previous prime is 11131021147. The next prime is 11131021211. The reversal of 11131021183 is 38112013111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11131021183 - 221 = 11128924031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131021103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565510591 + 5565510592.
It is an arithmetic number, because the mean of its divisors is an integer number (5565510592).
Almost surely, 211131021183 is an apocalyptic number.
11131021183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131021183 is an equidigital number, since it uses as much as digits as its factorization.
11131021183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 11131021183 its reverse (38112013111), we get a palindrome (49243034294).
The spelling of 11131021183 in words is "eleven billion, one hundred thirty-one million, twenty-one thousand, one hundred eighty-three".
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