Base | Representation |
---|---|
bin | 1010000111111010101000… |
… | …0011000101100101010101 |
3 | 1110102010100102021100012021 |
4 | 2201332222003011211111 |
5 | 2424333004434344312 |
6 | 35401321322253141 |
7 | 2226124235041522 |
oct | 241765203054525 |
9 | 43363312240167 |
10 | 11131113199957 |
11 | 3601751239703 |
12 | 12b934b3571b1 |
13 | 629875b1b78a |
14 | 2a6a6a818149 |
15 | 14482c10ec07 |
hex | a1faa0c5955 |
11131113199957 has 2 divisors, whose sum is σ = 11131113199958. Its totient is φ = 11131113199956.
The previous prime is 11131113199949. The next prime is 11131113199961. The reversal of 11131113199957 is 75999131113111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10497638880036 + 633474319921 = 3240006^2 + 795911^2 .
It is a cyclic number.
It is not a de Polignac number, because 11131113199957 - 23 = 11131113199949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131113197957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565556599978 + 5565556599979.
It is an arithmetic number, because the mean of its divisors is an integer number (5565556599979).
Almost surely, 211131113199957 is an apocalyptic number.
It is an amenable number.
11131113199957 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131113199957 is an equidigital number, since it uses as much as digits as its factorization.
11131113199957 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 229635, while the sum is 52.
The spelling of 11131113199957 in words is "eleven trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred ninety-nine thousand, nine hundred fifty-seven".
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