Base | Representation |
---|---|
bin | 1010000111111010101010… |
… | …0101001100111101111101 |
3 | 1110102010101001002200212211 |
4 | 2201332222211030331331 |
5 | 2424333014232034401 |
6 | 35401322242100421 |
7 | 2226124404050032 |
oct | 241765245147575 |
9 | 43363331080784 |
10 | 11131122143101 |
11 | 3601756297834 |
12 | 12b935234a711 |
13 | 62987793028c |
14 | 2a6a6baa5389 |
15 | 14482ccc9951 |
hex | a1faa94cf7d |
11131122143101 has 2 divisors, whose sum is σ = 11131122143102. Its totient is φ = 11131122143100.
The previous prime is 11131122143051. The next prime is 11131122143117. The reversal of 11131122143101 is 10134122113111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7207216759876 + 3923905383225 = 2684626^2 + 1980885^2 .
It is a cyclic number.
It is not a de Polignac number, because 11131122143101 - 29 = 11131122142589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131122143171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565561071550 + 5565561071551.
It is an arithmetic number, because the mean of its divisors is an integer number (5565561071551).
Almost surely, 211131122143101 is an apocalyptic number.
It is an amenable number.
11131122143101 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131122143101 is an equidigital number, since it uses as much as digits as its factorization.
11131122143101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 11131122143101 its reverse (10134122113111), we get a palindrome (21265244256212).
The spelling of 11131122143101 in words is "eleven trillion, one hundred thirty-one billion, one hundred twenty-two million, one hundred forty-three thousand, one hundred one".
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