11131199980 has 24 divisors (see below), whose sum is σ = 23389365888. Its totient is φ = 4449842688.

The previous prime is 11131199953. The next prime is 11131199987. The reversal of 11131199980 is 8999113111.

It is a super-3 number, since 3×11131199980³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11131199987) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130044 + ... + 197923.

It is an arithmetic number, because the mean of its divisors is an integer number (974556912).

Almost surely, 2^11131199980 is an apocalyptic number.

11131199980 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11131199980 is an abundant number, since it is smaller than the sum of its proper divisors (12258165908).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11131199980 is a wasteful number, since it uses less digits than its factorization.

11131199980 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329673 (or 329671 counting only the distinct ones).

The product of its (nonzero) digits is 17496, while the sum is 43.

The spelling of 11131199980 in words is "eleven billion, one hundred thirty-one million, one hundred ninety-nine thousand, nine hundred eighty".