1113120143 has 2 divisors, whose sum is σ = 1113120144. Its totient is φ = 1113120142.

The previous prime is 1113120119. The next prime is 1113120157. The reversal of 1113120143 is 3410213111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113120143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556560071 + 556560072.

It is an arithmetic number, because the mean of its divisors is an integer number (556560072).

Almost surely, 2^1113120143 is an apocalyptic number.

1113120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113120143 is an equidigital number, since it uses as much as digits as its factorization.

1113120143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1113120143 is about 33363.4552017623. The cubic root of 1113120143 is about 1036.3680457046.

Adding to 1113120143 its reverse (3410213111), we get a palindrome (4523333254).

The spelling of 1113120143 in words is "one billion, one hundred thirteen million, one hundred twenty thousand, one hundred forty-three".