11131202419 has 2 divisors, whose sum is σ = 11131202420. Its totient is φ = 11131202418.

The previous prime is 11131202393. The next prime is 11131202431. The reversal of 11131202419 is 91420213111.

It is a strong prime.

It is an emirp because it is prime and its reverse (91420213111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11131202419 - 2¹⁹ = 11130678131 is a prime.

It is a super-2 number, since 2×11131202419² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11131202393 and 11131202402.

It is not a weakly prime, because it can be changed into another prime (11131202449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565601209 + 5565601210.

It is an arithmetic number, because the mean of its divisors is an integer number (5565601210).

Almost surely, 2^11131202419 is an apocalyptic number.

11131202419 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131202419 is an equidigital number, since it uses as much as digits as its factorization.

11131202419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 11131202419 in words is "eleven billion, one hundred thirty-one million, two hundred two thousand, four hundred nineteen".